Question 248703: The sum of the digits of a positive two-digit integer is 45 less than the integer. What is the tens digit of the integer? Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! The sum of the digits of a positive two-digit integer is 45 less than the integer. What is the tens digit of the integer?
Let I be the number.
Let x be the tens digit and y the ones.
Then I = (10*x + y)
Also x + y = I - 45
So;
x + y = (10x + y) - 45
9x = 45
x=5.
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