SOLUTION: There were 37,000 people at a ball game in Los Angeles. The day's receipts were $262,000. How many people paid $11 for reserved seats and how many paid $6 for general admission?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: There were 37,000 people at a ball game in Los Angeles. The day's receipts were $262,000. How many people paid $11 for reserved seats and how many paid $6 for general admission?      Log On


   

Question 248653: There were 37,000 people at a ball game in Los Angeles. The day's receipts were $262,000. How many people paid $11 for reserved seats and how many paid $6 for general admission?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
R+G=37,000 OR R=37,000-G
11(37,000-G)+6G=262,000
407,000-11G+6G=262,000
-5G=262,000-407,000
-5G=-145,000
G=-145,000/-5
G=29,000 ANS. FOR THE NUMBER OF GENERAL ADMISSION TICKETS SOLD.
37,000-29,000=8,000 RESERVED SEAT TICKETS SOLD.
PROOF:
11*8,000+6*29,000=262,000
88,000+174,000=262,000
262,000=262,000