SOLUTION: Hi Tutors I hope I'm in the right section here. I need to simplify this{{{(1/4)(cos(1/4)(e^(-8x)))(-8(e^(-8x)))}}} Does this look right? {{{(cos(-2e^(-8x)))/4}}} Thanks for any

Algebra ->  Exponents -> SOLUTION: Hi Tutors I hope I'm in the right section here. I need to simplify this{{{(1/4)(cos(1/4)(e^(-8x)))(-8(e^(-8x)))}}} Does this look right? {{{(cos(-2e^(-8x)))/4}}} Thanks for any      Log On


   

Question 24864: Hi Tutors I hope I'm in the right section here.
I need to simplify this%281%2F4%29%28cos%281%2F4%29%28e%5E%28-8x%29%29%29%28-8%28e%5E%28-8x%29%29%29
Does this look right?
%28cos%28-2e%5E%28-8x%29%29%29%2F4
Thanks for any help.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
With further clarification, it seems that the original problem was to find the derivative of a function k%28x%29+=sin%28%281%2F4%29%2Ae%5E%28-8x%29%29. It turns out that the derivative of k(x) is
k'(x) =%281%2F4%29%2Acos%28%281%2F4%29%2Ae%5E%28-8x%29%29%2A%28-8e%5E%28-8x%29%29.

The question was actually, how do you simplify this answer!

k'(x) = -2+e%5E%28-8x%29%2Acos%28%281%2F4%29e%5E%28-8k%29%29

By the way, Calculus is usually not as hard as the algebra it takes to simplify it!! If you want to be GOOD at Calculus, make sure you have a GOOD algebra background before you get there!!

R^2 at SCC