SOLUTION: how do you solve these problems? 4. 180(n-2)/n =108 5. 180(n-2)/n = 120 6. 180(n-2)/n = 150

Algebra ->  Polygons -> SOLUTION: how do you solve these problems? 4. 180(n-2)/n =108 5. 180(n-2)/n = 120 6. 180(n-2)/n = 150       Log On


   

Question 248433: how do you solve these problems?
4. 180(n-2)/n =108
5. 180(n-2)/n = 120
6. 180(n-2)/n = 150
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
how do you solve these problems?
180%28n-2%29%2Fn=108
180%28n-2%29%2Fn=120
180%28n-2%29%2Fn=150

Steps:
1. Multiply by 2 on both sides of the equation to get rid of the fraction.
2. Mulitply 180 by each term inside the parenthesis.
3. Move all n terms on the left, and integers on the right.
4. Combine like terms.
5. Divide by coefficient of variable on both sides to find the value of n.

Here's the first one. I'll let you do the other two as they're very similar.
180%28n-2%29%2Fn=108
180n-360=108n
180n-108n=360
72n=360
n=360%2F72
n=5

Done with the first one!