SOLUTION: a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be
Algebra ->
Probability-and-statistics
-> SOLUTION: a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be
Log On
Question 248281: a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be found in the first 3 tests? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be found in the first 3 tests?
---------------
P(3 defective) = (3/5)(2/4)(1/3) = 2/20 = 1/10
=====================================================
Cheers,
Stan H.
(