SOLUTION: I'm having difficulty with this problem: If an object is propelled upward from the ground level with an initial velocity of 224 ft per second, it's height "h" in feet "t" seconds l

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Question 248253: I'm having difficulty with this problem: If an object is propelled upward from the ground level with an initial velocity of 224 ft per second, it's height "h" in feet "t" seconds later is given by the equation h=224t-16t^2. After how many seconds does the object hit the ground?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
h=224t-16t%5E2 Start with the given equation.


0=224t-16t%5E2 Plug in h=0 since the height at the ground level is zero.


-16t%5E2%2B224t=0 Rearrange the equation and terms.


-16t%28t-14%29=0 Factor out the GCF -16t


-16t=0 or t-14=0 Set each factor equal to zero.


t=0 or t=14 Solve for 't' in each equation


So the object will be at the ground level when t=0 or t=14. Ignoring the trivial answer of 0, this means that the object will hit the ground after 14 seconds.