SOLUTION: How do you solve 2log4-log3+2logx-4=0?
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Question 248198
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How do you solve 2log4-log3+2logx-4=0?
Answer by
Alan3354(69443)
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2log4-log3+2logx-4=0?
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2log(x) = 4 + log(3) - 2log(4)
All the terms on the right are constants
2log(x) =~ 3.273
log(x) = 1.6365
x = 43.3