SOLUTION: how do you get equation with the given properties (parallel to the line x-2y+5=0; passing through (0,0)

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Question 248082: how do you get equation with the given properties (parallel to the line x-2y+5=0; passing through (0,0)
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel would have the same slope.
Perpendicular would be -1 when the two slopes are multiplied
manipulate the equation till it is in the format
y=mx+b
m is the slope
x-2y+5=0
-2y=-x-5
divide by -2
minus over minus is plus
y=x/2+5/2
y=(1/2)(x)+5/2
where 1/2 is the slope the rise over run y over x
and 5/2 =y when x=0
so we want a line parallel to the original passing through (0,0)
y=mx+b
y=1/2*(x)+b
(0,0) also happens to be the y intercept.
we now have y=x/2