Question 248003: solve (x-2)^2(2x+1)less than or equal to 0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve (x-2)^2(2x+1) <= 0
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1st: Solve the EQUALITY:
x = 2 or x = -1/2
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Draw a number line and plot the two values, x = -1/2 and x = 2
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Now, pick a test value from each of the three line intervals to
see where the solutions for the inequality are.
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Test is (x-2)^2(2x+1) < 0
Testing x=-1 you get [(-3)^2](-1) < 0; true so solutions in (-inf,-1/2)
Testing x = 1 you get [(-1)^2(3)] < 0 ; false so no solutions in (-1/2,2)
Testing x = 3 you get [(1)^2*7] < 0 ; false so no solutions in (2,+inf)
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Final Answer {x | -inf < x < -1/2)}
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Cheers,
Stan H.
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