SOLUTION: Solve by the substitution method. 3x+2y=11 x-2=(-4y) what i did so far: x=2-4y 3(2-4y)+2y=11 6-12y+2y=11 6-14y=11 -14y=5 -14y/-14 =y 5/-14= ? when i divide i get a l

Algebra ->  Systems-of-equations -> SOLUTION: Solve by the substitution method. 3x+2y=11 x-2=(-4y) what i did so far: x=2-4y 3(2-4y)+2y=11 6-12y+2y=11 6-14y=11 -14y=5 -14y/-14 =y 5/-14= ? when i divide i get a l      Log On


   



Question 247958: Solve by the substitution method.
3x+2y=11
x-2=(-4y)
what i did so far:
x=2-4y
3(2-4y)+2y=11
6-12y+2y=11
6-14y=11
-14y=5
-14y/-14 =y
5/-14= ?
when i divide i get a long decimal with random numbers and i get confused >.<
then i tried:
3x+2y=11
x-2=(-4y)
x=(-4y)+2
3(-4y+2)+2y=11
(-12y)+6+2y=11
(-10y)=17
-10y/-10=y
17/-10=
Help? D:

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
x=2-4y
3(2-4y)+2y=11
6-12y+2y=11
6-14y=11 ___ OOPS!! ___ 6 - 10y = 11
-14y=5 ________________ -10y = 5
-14y/-14 =y ___________ y = -1/2
5/-14= ?

substituting ___ x = 2 - 4(-1/2)

x = 4