Question 247953: Hello,
This is my first time on this site, but I have heard that you help students with problems, and that it provide a better understanding I was wondering if you could help me with two problems.
I do not know how it works but here goes.
I am suppose to solve this problem without a graph, the instruction state that I need to find the minimum value of the following expression:
F(x)=(x-1)^2+1
On the next problem I do not need a graph but I need to find the line of symmetry for the following expression:
F(x)=6(x+2*sqrt5)^2-16.26
Again, if you can help me I do appreciated you kindness. A friend gave me your website I hope it okay.
Thank you
Sammie Ellis
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I am suppose to solve this problem without a graph, the instruction state that I need to find the minimum value of the following expression:
F(x)=(x-1)^2+1
Your equation is in the form y = a(x-h)^2+k
(h,k) is the vertex and is a minimum point if a is positive.
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Your problem:
a = 1; h = 1, k = 1
Vertex: (1,1) is the minimum point.
y = 1 is the minimum value for y.
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On the next problem I do not need a graph but I need to find the line of symmetry for the following expression:
F(x)=6(x+2*sqrt5)^2-16.26
The form is again y = a(x-h)^2 + k
where -h = 2sqrt(5) and k = -16.26 and a = 6
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h = -2sqrt(5)
The axis of symmetry for quadratics in this form is always x = h
Your axis of symmetry is x = -2sqrt(5)
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Cheers,
Stan H.
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