SOLUTION: Please help me solve this equation {{{log3(2x-1)-log3(x-4)=2}}}

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Question 247868: Please help me solve this equation log3%282x-1%29-log3%28x-4%29=2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Here are the important log rules
log (AB)=log(A)+log(B)
log(A/B)=log(A)+log(B)
C*log(A)=log(A^C)
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log%283%2C%282x-1%29%29-log%283%2C%28x-4%29%29=2
log%283%2C%282x-1%29%29-log%283%2C%28x-4%29%29=log%283%2C9%29
log%283%2C%282x-1%29%2F%28x-4%29%29=log%283%2C9%29
%282x-1%29%2F%28x-4%29=9
2x-1=9%28x-4%29
2x-1=9x-36
-7x=-35
x=5