SOLUTION: HUMPTY DUMPY JUMPED OFF A WALL. THE EQUAION h(t)=-16t^2+13t+8 DESCRIBES HIS HEIGHT ABOVE THE GROUND WHEN t REPRESENT THE NUMBER OF SECONDS SINCE HE JUMPED. USE THE TRACE FEATURE T

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Question 247832: HUMPTY DUMPY JUMPED OFF A WALL. THE EQUAION h(t)=-16t^2+13t+8 DESCRIBES HIS HEIGHT ABOVE THE GROUND WHEN t REPRESENT THE NUMBER OF SECONDS SINCE HE JUMPED. USE THE TRACE FEATURE TO ESTIMATE THE NUMBER OF SECONDS THAT ELAPSED FROM THE TIME HE JUMPED UNTIL HE HIT THE GROUND. ROUND YOUR THE ANSWER OF TENTHS.
Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Do not shout!
Try to copy the question as it was given to you.
I never learned to translate gibberish.
"ROUND YOUR THE ANSWER OF TENTHS"

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
h(t)=-16t^2+13t+8
When he hits the ground, h = 0
-16t^2 + 13t + 8 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case -16x%5E2%2B13x%2B8+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2813%29%5E2-4%2A-16%2A8=681.

Discriminant d=681 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-13%2B-sqrt%28+681+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%2813%29%2Bsqrt%28+681+%29%29%2F2%5C-16+=+-0.409249271918743
x%5B2%5D+=+%28-%2813%29-sqrt%28+681+%29%29%2F2%5C-16+=+1.22174927191874

Quadratic expression -16x%5E2%2B13x%2B8 can be factored:
-16x%5E2%2B13x%2B8+=+%28x--0.409249271918743%29%2A%28x-1.22174927191874%29
Again, the answer is: -0.409249271918743, 1.22174927191874. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B13%2Ax%2B8+%29

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Take the postive answer
t =~ 1.22 seconds
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I don't know what the "trace feature" is.