SOLUTION: log (base 81) 9= i have 81^x=9 but i do not know what to do next.
log (base x) (1/36)=-2 i have x^-2=(1/36) but i dont know what to do next
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-> SOLUTION: log (base 81) 9= i have 81^x=9 but i do not know what to do next.
log (base x) (1/36)=-2 i have x^-2=(1/36) but i dont know what to do next
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Question 247772: log (base 81) 9= i have 81^x=9 but i do not know what to do next.
log (base x) (1/36)=-2 i have x^-2=(1/36) but i dont know what to do next Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! log (base 81) 9= i have 81^x=9 but i do not know what to do next.
81 is 9^2, so 9 = 81^(1/2) or sqrt(81)
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log (base x) (1/36)=-2 i have x^-2=(1/36) but i dont know what to do next
x = 6
