Question 247671: The perimeter of a rectangle is 106 mm. The length is one more than three times the width. What is the area? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! P = 2L + 2W
L = 3W + 1 (length is 1 more than 3*width)
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substituting
P = 2(3W+1) + 2W
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P = 106 (given)
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substituting for P
2(3W+1) + 2W = 106
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multiply thru
6W + 2 + 2W = 106
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collect terms and subtract 2 from both sides
8W = 104
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divide both sides by 8
W = 13
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substitute back into the formula to solve for L
L = 3W+1 = 3(13)+1 = 40
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Checking to see if P = 2L + 2W
2L = 80
2W = 26
P = 106
OK
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Check to see if L = 3W + 1
3W = 39
+ 1 = 40
OK
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