SOLUTION: directions: find the standard form of the equation of each circle center at (0,3) and containing the point (3,7) please help me solve.

Algebra ->  Trigonometry-basics -> SOLUTION: directions: find the standard form of the equation of each circle center at (0,3) and containing the point (3,7) please help me solve.      Log On


   



Question 247371: directions: find the standard form of the equation of each circle
center at (0,3) and containing the point (3,7)
please help me solve.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
I haven't done this in a while so here goes.
formula for the center of a circle
(x-h)^2+(y-3)^2=r^2
(0,3) is the center (h,k)
so far we have
(x-0)^2+(y-3)^2=r^2
r= the distance from the center to the circle
the point 3,7 is on the circle
a^2+b^2=r^2
(7-3)^2+(3-0)^2=r^2
16+9=25
(x-0)^2+(y-3)^2=25
now to put it in standard form

x^2+(y-3)^2=25