SOLUTION: I was given this problem and now I am at a lost. The width of a retangle is 5 meters lass than twice its length. If it's area is 88 square meters, find the dimensions of the re

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: I was given this problem and now I am at a lost. The width of a retangle is 5 meters lass than twice its length. If it's area is 88 square meters, find the dimensions of the re      Log On


   



Question 247343: I was given this problem and now I am at a lost.
The width of a retangle is 5 meters lass than twice its length. If it's area is 88 square meters, find the dimensions of the rectangle. I know that A= L * W and the equation is W=2L-5 But I can't get any farther than that to answer the question. Thanks for your help.

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
W=2L-5
WL=88
(2L-5)L=88
2L^2-5L-88=0
(2L+11)(L-8)=0
L-8=0
L=8 ANS. FOR THE LENGTH.
W=2*8-5
W=16-5
W=11 ANS. FOR THE LENGTH.
PROOF:
8*11=88
88=88