You can put this solution on YOUR website! a right isosceles triangle has perimeter 12cm find its area?
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The sides will be s, s and s*sqrt(2)
2s + s*sqrt(2) = 12
s*(2 + sqrt(2)) = 12
s = 12/(2 + sqrt(2))
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Area = s^2/2
A = 144/(4 + 2 + 4sqrt(2)) = 72/(3 + 2sqrt(2))
A =~ 12.353 sq cm