SOLUTION: An employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day. When the number of $80 workers is increased by 50% and the number of
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: An employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day. When the number of $80 workers is increased by 50% and the number of
Log On
Question 247170: An employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day. When the number of $80 workers is increased by 50% and the number of $85 workers is decreased by 1/5, the new daily payroll is $1540, How many were originally employed at each rate? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! An employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day.
When the number of $80 workers is increased by 50% and the number of $85 workers is decreased by 1/5, the new daily payroll is $1540,
How many were originally employed at each rate?
:
Let x = no. of $80 employees originally
Let y = no. of $85 employees
:
Original payroll equation
80x + 85y = 1225
:
Employee change equation, (a 1/5 reduction means 4/5 or .8 are retained)
80(1.5x) + 85(.8y) = 1540
120x + 68y = 1540
:
Multiply the 1st equation by 1.5, subtract the above equation
120x + 127.5 = 1837.5
120x + 68y = 1540
----------------------eliminates x, find y
59.5y = 297.5
y =
y = 5 ea $85 employees originally
;
Find x using the 1st equation
80x + 85(5) = 1225
80x + 425 = 1225
80x = 1225 - 425
80x = 800
x = 10 ea $80 employees
:
:
Check solution in the change equation
80(1.5*10) + 85(.8*5) =
80(15) + 85(4) =
1200 + 340 = 1540
