SOLUTION: A chemist wants to mix a 5% alcohol solution with a 25% alcohol solution to obtain 8 liters of a 20% alcohol solution. How much (in liters) of the 25% solution should she use? T

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A chemist wants to mix a 5% alcohol solution with a 25% alcohol solution to obtain 8 liters of a 20% alcohol solution. How much (in liters) of the 25% solution should she use? T      Log On


   

Question 246958: A chemist wants to mix a 5% alcohol solution with a 25% alcohol solution to obtain 8 liters of a 20% alcohol solution. How much (in liters) of the 25% solution should she use?
Thanks in advance for your help.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.25x+.05(8-x)=.20*8
.25x+.4-.05x=1.6
.20x=1.6-.4
.20x=1.2
x=1.2/.20
x=6 liters of 25% alcohol is used.
8-6=2 liters of 5% alcohol is used.
Proof:
.25*6+.05*2=.20*8
1.5+.1=1.6
1.6=1.6