SOLUTION: how do i solve 8y-3(4-2y)=6(y+1)?

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Question 246956: how do i solve 8y-3(4-2y)=6(y+1)?
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
8y-3(4-2y)=6(y+1)
8y-12+6y=6y+6
14y-6y=6+12
8y=18
y=18/8
y=2.25
8*2.25-3(4-2*2.25)=6(2.25+1)
18-3(4-4.5)=6*3.25
18-3*-.5=19.5
18+1.5=19.5
19.5=19.5

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve 8y-3(4-2y)=6(y+1)
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Apply the distributive law to get:
8y-12+6y = 6y+6
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8y = 18
y = 9/4
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Cheers,
Stan H.