SOLUTION: If Sally can paint a house in 4 hours and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together? The furthest I can get is

Algebra ->  Proportions -> SOLUTION: If Sally can paint a house in 4 hours and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together? The furthest I can get is      Log On


   



Question 246801: If Sally can paint a house in 4 hours and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together?
The furthest I can get is the following:
Sally 4 hours/house = John 6 hours/house
I have no idea where to go from here. Any help would be appreciated.
thanks,
Carrie

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Use this method to solve all of these sorts of problems. Just plug in your numbers and do the arithmetic.

If A can do a job in x time periods, then A can do of the job in 1 time period. Likewise, if B can do the same job in y time periods, then B can do of the job in 1 time period.

So, working together, they can do



of the job in 1 time period.

Therefore, they can do the whole job in:



time periods.


John