Question 246759: A wheel is marked off into 8 sections numbered 1 to 8.
The numbers 1, 4, and 7 are colored red; the numbers 2 and 8
are colored blue; and the numbers 3, 5, and 6 are colored yellow.
You spin the wheel TWICE. . .
What is the probability of the first outcome being a number
BETWEEN 5 and 8 exclusive and the second outcome being blue?
a. 4/64
b. 2/8
c. 4/8
d. 4/16
Answer by Edwin McCravy(20060)   (Show Source):
You can put this solution on YOUR website! A wheel is marked off into 8 sections numbered 1 to 8.
The numbers 1, 4, and 7 are colored red; the numbers 2 and 8
are colored blue; and the numbers 3, 5, and 6 are colored yellow.
You spin the wheel TWICE. . .
What is the probability of the first outcome being a number
BETWEEN 5 and 8 exclusive and the second outcome being blue?
a. 4/64
b. 2/8
c. 4/8
d. 4/16
The sample space has 8 elements,
{1R, 2B, 3Y, 4R, 5Y, 6Y, 7R, 8B}
The probability that the first spin is between 5 and 8 exclusive is
the probability that it is 6Y or 7R. that's 2 out of 8 or  .
The probability that the second spin is blue is the probability that
it is 2B or 8B. that's also 2 out of 8 or .
These are independent events, so the probability that both will occur
is the product,  .
(I have no idea why whoever wrote this problem doesn't reduce fractions
but since they didn't, neither did I).
Edwin
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