write the first four terms of the sequence defined by the recursion formula
a1=2
an=-2an-1+2, n > 1
Substitute 2 for n:
an=-2an-1+2
a2=-2a2-1+2
a2=-2a1+2
Now substitute 2 for a1 since that is given:
a2=-2(2)+2
a2=-4+2
a2=-2
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Substitute 3 for n:
an=-2an-1+2
a3=-2a3-1+2
a3=-2a2+2
Now substitute -2 for a2 since that is what
we just calculated:
a3=-2(-2)+2
a3=4+2
a3=6
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Substitute 4 for n:
an=-2an-1+2
a4=-2a4-1+2
a4=-2a3+2
Now substitute 6 for a3 since that is what
we just calculated:
a4=-2(6)+2
a4=-12+2
a4=-10
So the first four terms, a1, a2, a3, a4 are 2, -2, 6, and -10, respectively.
Edwin