SOLUTION: The tens' digit of a two-digit number is 3 more than the units' digit,the number is 8 more than 6 times the sum of the digits,Find the number?
85,74,52,or 41
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-> SOLUTION: The tens' digit of a two-digit number is 3 more than the units' digit,the number is 8 more than 6 times the sum of the digits,Find the number?
85,74,52,or 41
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Question 246752: The tens' digit of a two-digit number is 3 more than the units' digit,the number is 8 more than 6 times the sum of the digits,Find the number?
85,74,52,or 41 Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! there are two ways to do this
one way uses the possible answers and works from them.
13*6+8=86
11*6+8=74
7*6+8=50
5*6+8=38
74
the other uses equalities and variables
10a+b=n
n=6(a+b)+8
10a+b=6(a+b)+8
a=3+b
a=
10(3+b)+b=6(3+b+b)+8
10(3+b)+b=6(3+2b)+8
30+10b+b=18+12b+8
30+11b=12b+26
subtract 26 from both sides
subtract 11b from both sides
b=4
a=7
n=74