SOLUTION: The largest of three numbers is 10 more than the smallest. The middle number is the average of the other two. If the sum of the three numbers is 42, what are the three numbers?
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Question 246748: The largest of three numbers is 10 more than the smallest. The middle number is the average of the other two. If the sum of the three numbers is 42, what are the three numbers? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! L=largest
m=middle
s=smallest
L=10+s
m=(L+s)/2
L+m+s=42
first substitute (L+s)/2 for m
L+((L+s)/2)+ s=42
now substitute 10+s for L
(10+s)+((10+s)+s)/2+s=42
simplify
10+2s+(10+2s)/2=42
2s+(10+2s)/2=32
multiply by 2
4s+10+2s=64
6s=54
s=9
L=10+s
m=(L+s)/2
substitute 9 in for s
