SOLUTION: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. a) Find h(1).

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. a) Find h(1).       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 246671: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped.
a) Find h(1).
b) How long does it take the ball to fall to the earth?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t^2 + 64, where t is the number of seconds after it is dropped.
a) Find h(1).
Simply substitute t with a 1 and solve:
h(1) = -16(1)^2 + 64
h(1) = -16(1) + 64
h(1) = -16 + 64
h(1) = 48 feet
.
b) How long does it take the ball to fall to the earth?
Simply substitute h(t) with a 0 and solve for t-- height when it falls to earth.
0 = -16t^2 + 64
16t^2 = 64
t^2 = 64/16
t^2 = 4
t = 2 seconds