SOLUTION: {{{log5(4x+1)= log5(2x+7)}}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: {{{log5(4x+1)= log5(2x+7)}}}      Log On


   

Question 246585: log5%284x%2B1%29=+log5%282x%2B7%29
Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
log5%284x%2B1%29=+log5%282x%2B7%29
I assume this is:
log base5 (4x+1) - log base5 (2x+7)?
Then 4x+1 = 2x+7.
Solve for x.