SOLUTION: Find the x-intercepts of y = x^2+4x

Algebra ->  Linear-equations -> SOLUTION: Find the x-intercepts of y = x^2+4x      Log On


   

Question 246361: Find the x-intercepts of y = x^2+4x
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
y = x^2 + 4x
y = x(x+4)
.
x=0
x=-4
.
Checking our work...
.
y = x^2 + 4x
x = 0
y = 0^2 + 4(0) = 0
OK
.
y = x^2 + 4x
x = -4
y = (-4)^2 + (4)(-4)
y = 16 + (-16) = 0
OK