SOLUTION: Could you please help me with this problem Use f(x)=4x to the -5 power and g(x)= x to the 3/4 power f(g(x)) and g(f(x))

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Could you please help me with this problem Use f(x)=4x to the -5 power and g(x)= x to the 3/4 power f(g(x)) and g(f(x))      Log On


   



Question 24636: Could you please help me with this problem
Use f(x)=4x to the -5 power and g(x)= x to the 3/4 power
f(g(x))
and g(f(x))

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
You do not say whether f(x) is %284x%29%5E%28-5%29 or 4%28x%29%5E%28-5%29. I shall take the latter, since that is what you wrote, although you may not have meant it.

f(x) = 4%28x%29%5E%28-5%29
g(x) = x%5E%283%2F4%29

Now functions are so easy, it is unbelievable that students struggle...bad teaching perhaps? :-)

ANY function will be written like h(a) = something. All this means is put the value in the bracket, here a, into the "something". This is ALL you do.

So, fg(x) says put the value of x into g first....ok doing this gives f(x%5E%283%2F4%29)

Now we have to do the function f. The definition of function f says, whatever is in the bracket, you raise to the power -5 and then multiply by 4. OK then, we have x%5E%283%2F4%29 as our "x", so lets do that:

f(x) = 4%28x%5E%283%2F4%29%29%5E%28-5%29. Now the question doesn't say simplify it, so you could leave it like that. It is correct. Or perhaps combine the 2 powers, giving f(x) = 4x%5E%28-15%2F4%29

OK, now for gf(x). Again, we will put the variable in the bracket (x) into function f first. We then put what is in the bracket into function g. That is ALL it is asking you do.

so, gf(x) --> g%284%28x%5E%28-5%29%29%29.

and now, this becomes %284%28x%5E%28-5%29%29%29%5E%283%2F4%29

Again, we could try to simplify this one, but i don't think trying to do that will give you anything of benefit.

Is this clearer now?

Have a look at my Lesson on functions on this website...it explains this topic.

jon.