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Question 246219: Write an equation in slope-intercept form for the line that passes through the point (-4,6) and is perpendicular to y=8x-7.
Answer by dabanfield(803)   (Show Source):
You can put this solution on YOUR website! Write an equation in slope-intercept form for the line that passes through the point (-4,6) and is perpendicular to y=8x-7.
The slope intercept form of a line is y = mx+b where m is the slope of the line and b is the value of y when the line crosses the y-axis (or when x = 0).
The line y = 8x-7 is in slope-intercept form so its slope is 8. The line perpendicular to this line has a slope that is the negative reciprical of 8 which is -1/8.
So the new line has the equation y = -1/8x + b
Since the new line passes through (-4,6) we can substitute x=-4 and y=6 in the equation above so:
6 = (-1/8)*-4 + b
6 = 1/2 + b
b = 5.5
The equation of the perpendicular line has the equation y = -1/8x + 5.5
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