SOLUTION: (a) Express the quadratic function in standard form.
(b) Find its vertex and its x and y intercepts.
(c) Sketch its graph.
f(x) = 2X^2 + X - 6
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-> SOLUTION: (a) Express the quadratic function in standard form.
(b) Find its vertex and its x and y intercepts.
(c) Sketch its graph.
f(x) = 2X^2 + X - 6
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Question 246203: (a) Express the quadratic function in standard form.
(b) Find its vertex and its x and y intercepts.
(c) Sketch its graph.
f(x) = 2X^2 + X - 6 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (a) Express the quadratic function in standard form.
(b) Find its vertex and its x and y intercepts.
Vertex occurs where x = -b/2a = -1/[2(2)] = -1/4
The corresponding y-value is f(-1/4) = 2(-1/4)^2+(-1/4)-6 = -6 1/8
Vertex: (-1/4 , -49/8)
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(c) Sketch its graph.
f(x) = 2X^2 + X - 6
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Cheers,
Stan H.
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