SOLUTION: In the sequence 16, 80, 48, 64, A, B, each term beyond the second term is the arithmetic mean (average) of the previous two terms. What is the value of B?
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Question 246053: In the sequence 16, 80, 48, 64, A, B, each term beyond the second term is the arithmetic mean (average) of the previous two terms. What is the value of B? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 16, 80, 48, 64, 56, 60
(80+16)/2=96/2=48
(80+48)/2=128/2=64
(64+48)/2=112/2=56 ans. for A
(64+56)/2=120/2=60 ans. for B
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