Question 245881: The product of 2 consecutive odd numbers is 63. What is the larger number? Found 3 solutions by College Student, unlockmath, Alan3354:Answer by College Student(505) (Show Source):
You can put this solution on YOUR website! Let x = a number
Let x+2 = its consecutive odd number
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Since the product of two consecutive odd numbers is 63, the equation becomes:
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Let's work out the algebra.
Factor:
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In order to make our above equation true, the solution set is x = {7,-9}.
Let's check which one works for our problem:
. <--- 7 works!
So, x=7 and x+2=9.
. <--- -9 also works!
So, x=-9 and x+2=-7.
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Both solution sets fit our criteria.
Both are odd numbers and both are odd consecutives which product is 63.
You can put this solution on YOUR website! Hello,
The way to do this is first let x be an odd number and the next odd number would be x+2. Make sense? Now we can set up an equation like this:
x(x+2)=63 Distribute this so it looks like:
x^2+2x=63 Subtract 63 from both sides gives us:
x^2+2x-63 This can be factored into:
(x+9)(x-7)=0 Solve x will be:
x=-9
x=7
From the two answers only 7 makes sense, so the larger number would be 9.
The above is how to solve it using algebra.
There is a faster way to figure it out by just thinking what two numbers multiplied together gives us 63. Of course the answer is 7 and 9
RJ Toftness
Check out my book at www.math-unlock.com
You can put this solution on YOUR website! The sqrt(63) is almost 8.
The 2 odd numbers are adjacent to 8, = 7 and 9.
Also, -7 and -9.
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Always use the easiest and quickest method.
It saves time, which is important on tests, and there's less chance of making an error.
