SOLUTION: Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rationa

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Question 245864: Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rational solution; or two different imaginary solutions.
25x^2 - 10x + 1 = 0

Found 2 solutions by solver91311, jsmallt9:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The discriminant is the part of the quadratic formula under the radical, namely:



Two real and unequal roots. If is a perfect square, the roots are rational. Otherwise, they are irrational.

One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. The Fundamental Theorem of Algebra still holds because it allows counting roots up to the limits of their multiplicity.

A conjugate pair of complex roots of the form where is the imaginary number defined by

Terminology note: Rarely will you find a quadratic with purely imaginary roots. A quadratic that does not have real roots generally has complex number solutions which have a real part and an imaginary part. Hence, to say that a quadratic has "two different imaginary solutions" is almost always incorrect.

John


Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic formula is:
x+=+%28-b+%2B-+sqrt%28b%5E2+-4ac%29%29%2F2a
The expression in the square root, b%5E2+-+4ac, is called the discrimnant, because its value can be used to discriminate between the different types of solutions that are possible:
  • b%5E2+-+4ac+%3E+0 results in two real solutions
    • If b%5E2+-+4ac is a perfect square (like 4, 9 64, 100, etc.) then you get two rational solutions.
    • If b%5E2+-+4ac is a not perfect square then you get two irrational solutions.
  • If b%5E2+-+4ac+=+0 then you get a single real (and rational since 0 is a perfect square) solution.
  • If b%5E2+-+4ac+%3C+0 then you get two complex solutions. (Note: you only get imaginary solutions if the discriminant is negative and b = 0!)

The logic behind all of this is:
  • Only zero has a single square root. Any other number will have two square roots, one positive and one negative.
  • The square roots of positive numbers are real (either rational or irrational).
  • The square roots of negative numbers are imaginary. And these imaginary roots, combined with the real number, the -b, in the numerator of the quadratic formula make the solutions complex (unless b = 0 in which case the solutions are pure imaginary numbers).

The discriminant of your equation
25x%5E2+-+10x+%2B+1+=+0
is
%28-10%29%5E2+-+4%2825%29%281%29
which simplifies to
100+-+4%2825%29%281%29
100+-+100
0
Since the discriminant of 25x%5E2+-+10x+%2B+1+=+0 is 0, there will be a single rational root.