SOLUTION: Solve the problem.
An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance travele
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An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance travele
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Question 245861: Solve the problem.
An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground? Show your work. Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! Since the plane is 540 feet above the ground, s is 540 so we have:
540 = 16t^2 + 27t or
16t^2 + 27t - 540 = 0
Solve for t. One way to do this would be to use the quadratic formula where a=16, b=27 and c=-540.
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