SOLUTION: how would you solve this quadratic equation y squared plus 3y plus 2=o

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Question 245836: how would you solve this quadratic equation y squared plus 3y plus 2=o
Found 2 solutions by College Student, dabanfield:
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
Problem: y%5E2%2B3y%2B2
.
First factor the equation:
%28y%2B2%29%28y%2B1%29=0
Then find the solution set:
y = {-2,-1}
.
Done!

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
Factor y^2 + 3y + 2 into (y+2)*(y+1)
Now you have:
(y+2)*(y+1) = 0
So y+2 = 0 and/or y+1 = 0 must be true.
The solutions to the equation then are:
y = -2 and y = -1