SOLUTION: Sue has 4 blocks more then jane, and Rod has 2 more then both jane and sue together. if the total nimber of blocks is 42, how many blocks do sue, jane and rod each have.
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Question 245732: Sue has 4 blocks more then jane, and Rod has 2 more then both jane and sue together. if the total nimber of blocks is 42, how many blocks do sue, jane and rod each have.
ex. of how it should be set up...
sue- 4+x
jane- x
rod- x+9
thanks for your help. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! let sue=s
jane=j
and rod=r
s+j+r=42
s=j+4
r=j+s+2
substitute
j+4+j+j+s+2=42
j+4+j+j+j+4+2=42
4j+10=42
4j=32
j=8
s=12
r=8+12+2=22
check
8+12+22=42
42=42
