SOLUTION: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that katie is now. How old is each now?

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Question 245670: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that katie is now. How old is each now?
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
Four years ago:
Anne = x
Katie = 2x
.
Today (four years later)
Anne = x+4
Katie = 2x+4
.
In six years Anne will be the same age Katie is now. So our equation becomes:
x%2B4%2B6=2x%2B4
Combine like terms and solve for x to find today's Anne's age.
I'll let you take it from here. :)