SOLUTION: i'm having trouble with my homework on solving absolute value equations. I am taking advanced algebra 1 heres the question... x-2 (in absolute value bars)

Algebra ->  Absolute-value -> SOLUTION: i'm having trouble with my homework on solving absolute value equations. I am taking advanced algebra 1 heres the question... x-2 (in absolute value bars)       Log On


   



Question 245533: i'm having trouble with my homework on solving absolute value equations. I am taking advanced algebra 1
heres the question...
x-2 (in absolute value bars)
x-2= x/3
can you please help!

Found 2 solutions by College Student, edjones:
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
Is your question saying |x-2|=x/3 ?
If so, here's how we solve it:
.
x-2=x%2F3
Multiply by 3 on both sides to get rid of the fraction, we get:
3%28x-2%29=x
Distribute:
3x-6=x
Let's solve for x by combining like terms:
3x-x=6
2x=6
x=6%2F2
x=3
.
Now substitute this value in the original expression:
|x-2|=x/3
|3-2|=3/3
|1|=1
1=1
.
Done!

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
|x-2|=x/3
.
x-2=x/3
3x-6=x
2x=6
x=3
.
x-2=-x/3
3x-6=-x
4x=6
x=6/4=3/2
.
Ed