Question 24532: PLEASE HELP WITH THIS TOO!
In a certain triangle, the first angle measures 9 degrees less than the second angle. The third angle measures 3 degrees more than the second angle. Find the measures of all three angles.
I can solve this if I have the degrees of two sides, but this doesn't give any. I thought I should let x=second angle, x-9=first angle, and x+3=third angle but I didn't know where to go from there(or if that was the way to start)
THIS IS DUE BY 01/17/06. THANKS FOR YOUR TIME!
Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website! Let the first angle be A, the second angle be B and the third angle be C.
From the problem description, you can write:
A = B-9
C = B+3
And you already know (or should know) that for any plane triangle: A+B+C = 180 degrees.
So, in A+B+C = 180, substitute for A and C the first two equations:
(B-9) + B + (B+3) = 180 Simplify and solve for B.
3B - 6 = 180 Add 6 to both sides of the equation.
3B = 186 Divide both sides by 3.
B = 62
A = B-9
A = 62-9 = 53
C = B+3
C = 62+3 = 65.
The three angles are:
A = 53 degrees.
B = 62 degrees.
C = 65 degrees.
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