Question 245135: please help me solve this quadratic equations:
Find the center of the following equation x^2-y^2+24+4y+28=0:
here are the possible answers:
a)(-4,3)
b)(4,3)
c)(8,-6)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve this quadratic equations:
Find the center of the following equation x^2-y^2+24+4y+28=0:
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(x-0)^2 -(y^2-4y+?) = -52
(x-0)^2 -(y^2-4y+4) = -52-4
(x-0)^2 -(y-2)^2 = -56
(y-2)^2 - (x-0)^2 = 56
Center: (0,2)
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Note: I think your post of the problem is missing something.
You are probably missing an "x" term.
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Cheers,
Stan H.
here are the possible answers:
a)(-4,3)
b)(4,3)
c)(8,-6)
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