SOLUTION: given log(base a)x=4, log(base a)y=3, and log(base a)z=2 for constants x, y,z. find the value of the logarithm. log(base a)((5th root of y^3 times x^6 times z^4)/(5th root of z^

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: given log(base a)x=4, log(base a)y=3, and log(base a)z=2 for constants x, y,z. find the value of the logarithm. log(base a)((5th root of y^3 times x^6 times z^4)/(5th root of z^      Log On


   



Question 244998: given log(base a)x=4, log(base a)y=3, and log(base a)z=2 for constants x, y,z. find the value of the logarithm.
log(base a)((5th root of y^3 times x^6 times z^4)/(5th root of z^6 times x^2)

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you are given:

log(a,x) = 4
log(a,y) = 3
log(a,z) = 2

you want to find:



since root%28n%2Ca%29%2Froot%28n%2Cb%29+=+root%28n%2C%28a%2Fb%29%29, your equation becomes:

log%28a%2C%28%28root%285%2C%28y%5E3%2Ax%5E6%2Az%5E4%29%2F%28z%5E6%2Ax%5E2%29%29%29%29%29

since root%285%2Ca%29+=+a%5E%281%2F5%29, your equation becomes:

log%28a%2C%28%28%28y%5E3%2Ax%5E6%2Az%5E4%29%2F%28z%5E6%2Ax%5E2%29%29%5E%281%2F5%29%29%29%29

since log(a^b) = b*(log(a), your equation becomes:



since log(a/b) = log(a)/log(b), your equation becomes:



since log(a*b) = log(a) + log(b), your equation becomes:



since log(a^b) = b*log(a), your equation becomes:



from here on it's just a straight substitution since you are given:

log(a,x) = 4
log(a,y) = 3
log(a,z) = 2

your equation of:



becomes:

%281%2F5%29+%2A+%283%2A3+%2B+6%2A4+%2B+4%2A2+-+6%2A2+-+2%2A4%29 which becomes:

%281%2F5%29+%2A+%289%2B24%2B8-12-8%29 which becomes:

%281%2F5%29+%2A+%2821%29 which becomes:

21%2F5