Question 244874: x^4-81
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! If you had a "difference of squares":
a^2 - b^2
you can factor as:
(a+b)(a-b)
.
For your problem:
x^4-81
we can rewrite as a "difference of squares":
(x^2)^2 - 9^2
Thus we can factor as:
(x^2+9)(x^2-9)
But wait, the right term is also a "difference of squares":
(x^2+9)(x^2-3^2)
(x^2+9)(x+3)(x-3) -- final answer
|
|
|
