SOLUTION: this is my question: Determine whether the system has one solution,no solution, or many solutions: y=2/3x
2x-y=-4
could somebody please explain how
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-> SOLUTION: this is my question: Determine whether the system has one solution,no solution, or many solutions: y=2/3x
2x-y=-4
could somebody please explain how
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Question 24428: this is my question: Determine whether the system has one solution,no solution, or many solutions: y=2/3x
2x-y=-4
could somebody please explain how to get the answer? Thank you. Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! The first equation is ambiguous!
Is it or ???
Let's assume that it is the first case.
You can solve questions like this by graphing or algebraically.
Let's look at the graphic solution:
The red line is
The green line is This is the 2nd equation written in terms of y.
Now solve algebraically by substitution:
1) Substitute this equation for y in the second equation.
2)
2) Simplify and solve for x. Multiply both sides by the multiplicative inverse of 4/3 (that's 3/4) Now substitute this value of x into either one of the two original equations and solve for y. Take the first equation,
There is only one solution, it is: (-3, -2) Compare this with the intersection point of the two lines on the graph.
Now assume that the first equation is: and let's look at the graph:
As you can see, there would be two solutions (points of intersection) in this case.