SOLUTION: What is the root of 49x^2-25=0?
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Question 244006
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What is the root of 49x^2-25=0?
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49x^2-25=0 => (7x)^2 - 5^2 = 0 => (7x + 5)(7x-5) = 0
=> x = 5/7 and -5/7