Question 243770: 5. A red ball and a green ball are simultaneously tossed into the air. The red ball is given an initial velocity of 96 feet per second, and its height, t seconds after it is tossed is( -16t^2 + 96t )feet. The green ball is given an initial velocity of 80 feet per second, and its height, t seconds after it is tossed is (-16t^2 + 80t ) feet.
5.1. Write the algebraic expression, in simplest form, that represents the difference in heights between the two balls at any time, t.
5.2. How much higher is the red ball after 2 seconds.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A red ball and a green ball are tossed into the air. The red ball is given an
initial velocity of 96 feet per second and its height "t" seconds after it is
tossed is -16t^2 + 96t feet.
The green ball is given an initial velocity of 80 feet per second and its height
"t" seconds after being tossed is -16t^2 +80t feet.
:
5.1. Write the algebraic expression, in simplest form, that represents the difference in heights between the two balls at any time, t.
D(t) = (-16t^2 + 96t) - (-16t^2 +80t)
:
Remove brackets
D(t) = -16t^2 + 96t + 16t^2 - 80t
:
combine like terms:
D(t) = 16t
:
5.2. How much higher is the red ball after 2 sec?
D(t) = 16(2)
D(t) = 32 ft difference after 2 seconds
:
Looks like this:
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