SOLUTION: a diagonal of a rectangle is 3 in longer than a side of the square. Find the length of a side and the length of a diagonal.

Algebra ->  College  -> Linear Algebra -> SOLUTION: a diagonal of a rectangle is 3 in longer than a side of the square. Find the length of a side and the length of a diagonal.      Log On


   



Question 24373: a diagonal of a rectangle is 3 in longer than a side of the square. Find the length of a side and the length of a diagonal.
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
diagonal of a rectangle is 3 in longer than a side of the square. Find the length of a side and the length of a diagonal.
LET SIDE OF SQUARE =X
DIAGONAL LENGTH =X+3
IN A SQUARE WE HAVE FROM PYTHOGARUS THEOREM
SIDE^2+SIDE^2=DIAGONAL^2
X^2+X^2=(X+3)^2=X^2+9+6X
2X^2-X^2-9-6X=0
X^2-6X-9=0
x+=+%286+%2B-+sqrt%28%28-6%29%5E2-4%2A1%2A%28-9%29+%29%29%2F%282%2A1%29+
x+=+%286+%2B-+sqrt%2836%2B36+%29%29%2F2+
x+=+%286+%2B-+6sqrt%282%29%29%2F2+%29
x+=+%283+%2B-+3sqrt%282%29+%29
x+=+%283+%2B+3sqrt%282%29+%29
HENCE SIDE =x+=+%283+%2B+3sqrt%282%29+%29AND DIAGONAL IS x+=+%286+%2B+3sqrt%282%29+%29