SOLUTION: Graph the equation using the slope and the y-intercept y=1/5x+8 Can anyone help here and i need to see a graph if possible thanks

Algebra ->  Linear-equations -> SOLUTION: Graph the equation using the slope and the y-intercept y=1/5x+8 Can anyone help here and i need to see a graph if possible thanks      Log On


   

Question 243616: Graph the equation using the slope and the y-intercept
y=1/5x+8
Can anyone help here and i need to see a graph if possible thanks
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at y=%281%2F5%29x%2B8 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=1%2F5 and the y-intercept is b=8


Since b=8 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 1%2F5, this means:

rise%2Frun=1%2F5


which shows us that the rise is 1 and the run is 5. This means that to go from point to point, we can go up 1 and over 5



So starting at , go up 1 unit


and to the right 5 units to get to the next point



Now draw a line through these points to graph y=%281%2F5%29x%2B8

So this is the graph of y=%281%2F5%29x%2B8 through the points and