SOLUTION: Find two positive numbers such the sum of the first and twice the second is 100 and their product is as large as possible?

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Question 243614: Find two positive numbers such the sum of the first and twice the second is 100 and their product is as large as possible?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Find two positive numbers such the sum of the first and twice the second is 100 and their product is as large as possible?

Let t = the first number
Let x = the second number

>>...the sum of the first and twice the second is 100...<<

t%2B2x+=+100

We want to maximize the product xy.  

Let y = the product = tx

y=tx

Solve t%2B2x+=+100 for t
      t=+100-2x

Substitute 100-2x for t in

y+=+tx

y+=+%28100-2x%29x

y+=+x%28100-2x%29

y+=+100x-2x%5E2

If you are taking algebra, not calculus, then find the
vertex of the parabola

y=-2x%5E2%2B100x%2B0

Since the coefficient of x%5E2 is negative, the
graph opens downward and thus reaches a maximum at the
vertex.

The formula for the x-coordinate of the vertex = -b%2F%282a%29

So the x-coordinate of the vertex is -b%2F%282a%29=-%28100%29%2F%282%28-2%29%29=100%2F4=25

So the value of x is 25

Now substitute 25 for x in 

t%2B2x+=+100

t%2B2%2825%29+=+100

t%2B50+=+100

t=50

So the two numbers are

first = 25
second = 50

---------------------------------------------

If you're taking calculus, you would do it by
taking the derivative of 

y+=+100x-2x%5E2

%28dy%29%2F%28dx%29=100-4x

and set the derivative = 0

100-4x=0

-4x=-100

x=25

and as in the algebra way, t=100-2x=100-2%2825%29=100-50=50 

Edwin